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Answer 1

Explanation:

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t =( √x) + 2

(t - 2)² = x

t² + 4 - 4t = x

dx/dt = v = 2t -4

v(0) = -4

v(1) = -2

v(2) = 0

v(3) = 2

v(4) = 4

Clearly, velocity is changing sign .

So, displacement will be zero

Answer 2

Here , we have been given an equation t=√x + 2.

Let's find X.

√X = t-2

X = (t - 2)^2

X = t^2-4t+4

Now let's find velocity.

v = dx/dt = 2t-4.

Put dx/dt = 0.

0=2t - 4

2t = 4

t = 2

By this way , we get the time at which the particle's velocity is zero.

We know,

a= dv/dt = 2

And

F = ma = 2m

and

x(initial) =( t-2)^2 = (4-2)^2 = 4 m

x (final) = 4 m

so displacement = 0 m

Work = Fd = 2m × 0 = 0

(a)Zero