Question

PLZ ANSWER FAST I WILL MARK YOU AS BRAINIEST
A number is divided into parts such that one part one part is 10 more than the other . If the two parts are in the ratio 5:3 , find the number and the two parts.

Answer 1

Answer:

Since the two parts are in the ratio 5:3, then let the first number be 5x and second number be 3x. As second number is 10 more than the other, so it will be 3x+10.

5x=3x+10

2x=10

x=5

The first number becomes 5(5)=25 and second number becomes 3(5)=15.

The new number will be 25+15=40.

pls mark my answer as brainliest!!!!

Answer 2

A number is divided in to two parts such that one part is 10 more than the other. If the two parts are in the ratio 5:3, find the number and the two parts.

solution:

      let one part of number = x

          therefore ,  other part of number = x+10

  according to question ,

            x+10/x=5/3

          3(x+10)= 5x

          3x+30 =5x

            30 = 5x -3x

            30 = 2x

    or x=30/2

        x=15

therefore one part of number = 15

and other part = 15+10 =25

hence number = 15+25 =40

hope this helps you!!!

pls mark me as brilliant