Chemistry, asked by srivinayakaservices1, 3 days ago

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Answered by ak8842340
1

Answer:

1.given that

Mass of the 2n, omega = Molar mass of = 10 ,6 2n,M=65,32g/ Number of moles mol 1 + x = 60/M = (10g)/(65.38g / m * o * l)

= 500 3269 mol

:. Number alpha ^ f atomis, N = n*N_{A} = 500 3269 *6.022*10^ 23 = underline 2.2108*10^ 22 atams

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