Math, asked by DiyaPrithiani, 4 months ago

plz answer fast...
icse maths chapter 1 class 9
rational and irrational nos.​

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Answered by deenabandhannsboamdu
2

Answer:

 \frac{4 - 2 \sqrt{3} }{2}  \\  = 2 -   \sqrt{3}

Step-by-step explanation:

FIRST MULTIPLY BOTH THE NUMERATOR AND DENOMIMATOR WITH THE CONJUGATE OF THE DENOMINATOR (√3-1)

THEREFORE

 \frac{( \sqrt{3}  - 1)( \sqrt{3}  -  1)}{( \sqrt{3} + 1)( \sqrt{3}  -  1)}

SIMPLIFYING WE GET AS

 \frac{4 - 2 \sqrt{3} }{2}  \\  = 2 -   \sqrt{3}

Answered by Anonymous
1

Answer:

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Solution: (√3-1)/(√3+1)

Multiply both numerator and denominator by (√3-1)

{(√3-1)×(√3-1)}/{(√3+1)(√3-1)}

= {√3 - 1}²/{(√3)² - 1²}

= (3-2√3+1)/(3-1)

= (4-2√3)/2

= 2(2-√3)/2

= 2-√3

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