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icse maths chapter 1 class 9
rational and irrational nos.
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Answer:
Step-by-step explanation:
FIRST MULTIPLY BOTH THE NUMERATOR AND DENOMIMATOR WITH THE CONJUGATE OF THE DENOMINATOR (√3-1)
THEREFORE
SIMPLIFYING WE GET AS
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Solution: (√3-1)/(√3+1)
Multiply both numerator and denominator by (√3-1)
{(√3-1)×(√3-1)}/{(√3+1)(√3-1)}
= {√3 - 1}²/{(√3)² - 1²}
= (3-2√3+1)/(3-1)
= (4-2√3)/2
= 2(2-√3)/2
= 2-√3
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