plz answer fast if alpha and beta are zeroes of the polynomial xsq-2x-8 then form a quadratic polynomial whose zeros are 2alpha and 2beta
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Answered by
3
α=-2×2
=-4
β=-8×2
=-16
to form q.p=x^2-sum of x + product
=x^2-4x-16.
=-4
β=-8×2
=-16
to form q.p=x^2-sum of x + product
=x^2-4x-16.
Answered by
2
= p(x) = x2-2x-8
= sum of zeroes = α+β
= -b/a = 2/1 = 2................(1)
= products or zeros = αβ
= c/a = -8/1 = -8.................(2)
= Given zeros are 2α and 2β,
= sum of zeroes = 2α+2β
= 2(α+β)
= 2 . 2 = 4. (using (1))
= product of zeroes = 2α . 2β
= 4αβ = 4 . -8 = -32..................(using(2))
= the required polynomial ,
=p(x) x2-4x-32.
= sum of zeroes = α+β
= -b/a = 2/1 = 2................(1)
= products or zeros = αβ
= c/a = -8/1 = -8.................(2)
= Given zeros are 2α and 2β,
= sum of zeroes = 2α+2β
= 2(α+β)
= 2 . 2 = 4. (using (1))
= product of zeroes = 2α . 2β
= 4αβ = 4 . -8 = -32..................(using(2))
= the required polynomial ,
=p(x) x2-4x-32.
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