Question

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Answer 1

Answer:

Suppose, the age of the son six year

before was x

. mother’s age six year before was x²

. present age of the son is (x + 6) and

present age of the mother is (x² + 6)

Three years hence, son’s age will be (x

+ 9) and mother’s age will be (x² + 9)

by given condition,

x² + 9 = 3(x + 9)

“x²-3x+9-27=0

x² -3x-18=0

. (x - 6) (x + 3) =0

X=6 0r x=-3

But age cannot be negative -. x is not equal to -3 )

-. sons present age =x+6= 6+6 =12

years.

mother's present age = x² + 6 = 36+ 6

= 42 years.

HOPE YOU WILL UNDERSTAND ☺️

Now do as you said......