Question

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Answer 1

Step-by-step explanation:

Arc AB/ Arc BC = angle AOB / angle BOC 3/2 = 96°/ angle BOC angle BOC = 64° Holding arc BC Angle COB = 2×angle CAB ( Angle subtended on the centre is double the angle subtended at the circumference by the same arc ) 64°/2 = angle CAB = 32° Holding chord AB Angle AOB=2×angle ACB(same as above) 96°/2 = angle ACB = 48° ACBD is a cyclic quadrilateral Angle ACB + Angle ADB =180° ( opposite angles of a cyclic quadrilateral are supplementary) 48° + angle ADB =180° Angle ADB = 180° - 48° = 132°