Question

plz answer fast it is urrgent ​

Answer 1

Answer

Q7. Choice b) $z-y$

Q8. Choice c) $5^4=625$

Q9. Choice d) $a^m\times a^n=a^{m+n}$

Q10. Choice a) 180°

Explanation

Q7. Subtracting a number is denoted by '-'.

Q8. $5^4=5\times 5\times 5\times 5$, so $5^4=625$.

Q9. We know that

• $\mathrm{a^m=\underset{m\:times}{a\times a\times ...\times a}}$
• $\mathrm{a^n=\underset{n\:times}{a\times a\times ...\times a}}$
• $\mathrm{a^{m+n}=\underset{m+n\:times}{a\times a\times ...\times a}}$

Since $\mathrm{a^m\times a^n=\underset{m+n\:times}{a\times a\times ...\times a}}$, we get $\mathrm{a^m\times a^n=a^{m+n}}$.

Q10. Let's draw a parallel line against a side that passes through a vertice.

By property of parallel line, the angles of a triangle sum to 180°. (Refer to the attachment.)

Answer 2

Answer:

Answer

Q7. Choice b) z-yz−y

Q8. Choice c) 5^4=6255

4

=625

Q9. Choice d) a^m\times a^n=a^{m+n}a

m

×a

n

=a

m+n

Q10. Choice a) 180°

Explanation

Q7. Subtracting a number is denoted by '-'.

Q8. 5^4=5\times 5\times 5\times 55

4

=5×5×5×5 , so 5^4=6255

4

=625 .

Q9. We know that

\mathrm{a^m=\underset{m\:times}{a\times a\times ...\times a}}a

m

=

mtimes

a×a×...×a

\mathrm{a^n=\underset{n\:times}{a\times a\times ...\times a}}a

n

=

ntimes

a×a×...×a

\mathrm{a^{m+n}=\underset{m+n\:times}{a\times a\times ...\times a}}a

m+n

=

m+ntimes

a×a×...×a

Since \mathrm{a^m\times a^n=\underset{m+n\:times}{a\times a\times ...\times a}}a

m

×a

n

=

m+ntimes

a×a×...×a

, we get \mathrm{a^m\times a^n=a^{m+n}}a

m

×a

n

=a

m+n

.

Q10. Let's draw a parallel line against a side that passes through a vertice.

By property of parallel line, the angles of a triangle sum to 180°. (Refer to the attachment