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9.
44g of CO2 = 1 mol
(12+(2*16=44)
88g of CO2 = 1*88/44
= 2 mol
13.
a). MgCl2
b). CaO
c). CaCO3
d). AlCl3
44g of CO2 = 1 mol
(12+(2*16=44)
88g of CO2 = 1*88/44
= 2 mol
13.
a). MgCl2
b). CaO
c). CaCO3
d). AlCl3
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