Question

plz answer fast its important right answers will be marked as brainilist ​

Answer 1

$f(t) = {t}^{2} - 6t + 5$

To Solve for t when f(t) = 0

${t}^{2} - 6t + 5 = 0$

${t}^{2} - 2(3)(t) + {3}^{2} - {3}^{2} + 5 = 0$

$( {t} - 3) ^{2} - 4= 0$

$\sqrt{ {(t - 3)}^{2} } = \pm \sqrt{4}$

$t - 3 = \pm2$

$t = \pm 2 + 3$

$\implies \boxed{ t = 5 , 1}$

Verification:

${t}^{2} - 6t + 5 = 0$

${t}^{2} - 5t - t + 5 = 0$

$t(t - 5) - (t - 5) = 0$

$(t - 5)(t - 1) = 0$

$\implies t = 5 \: \: and \: \: 1$