Question

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Answer 1

Answer:

Apd congruent Cpb

ad = bc

ap = pc

dp = bp

apd congruent Cpb by sss

hope it's useful for you

Answer 2

Answer:

In Δ APD and ΔCPB

Given

AD parallel to BC

To Prove

Δ APD ~ Δ CPB

Proof

Angle DAP = Angle BCP ( by A. I. A)

Angle APD = Angle BPC ( by V. O.A)

Angle ADP = Angle CBP ( by A. I. A)

So, Δ APD ~ Δ CPB by (A. A. A)