Question

plz answer fast its important right answers will be marked as brainilist and plz answer step by step ​
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Answer 1

Given: PQ || DE

Proof:

In both the triangles,

DE || PQ (given)

So,

angle FDE = angle FPQ (CORRESPONDING ANGLES)

angle DEF = angle PQF (CORRESPONDING ANGLES)

So, by AA Similarity, triangle DEF ~ triangle PQF

Since, triangle DEF ~ triangle PQF,

$\frac{DE}{PQ} = \frac{DF}{PF} = \frac{EF}{QF}$

By solving, we get

DE = 3 x 1.8 = 5.4

So, DE = 5.4cm

     DP = 3.1cm