plz answer fast its urgent
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Answer:
In the given figures i.e., Tri.PAB and Tri. QAB
AP=AQ (GIVEN)
BP=BQ (GIVEN)
AB=AB (COMMON)
Therefore, Tri. PAB is congruent to Tri. QAB by S.S.S congruence condition
Angle PAB = Angle QAB (CPCT)
Angle PBA = Angle QBA (CPCT)
So, AB bisects Angle PAQ and Angle PBD since it divides it into two equal parts
HOPE IT HELPS
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2
Answer:
I really don't know sorry
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