plz answer fast its urgent need for exam
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rohitpimoli18042:
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Now, according to question we have given,
x + 2 = 0
x = - 2
p(x) = ax³ + bx² + x - 2
Put the value of the x in above equation
p(-2) = a (-2)³ + b (-2)² - 2 - 2 = 0
- 8a + 4b - 4 = 0
- 2a + b - 1 = 0 ............(1)
In question it is also said that when p(x) is divided by (x - 2) then it leaves out remainder 4
Now value of x = 2 [As x - 2 = 0]
p(2) = a(2)³ + b(2)² + 2 - 2 = 0
= 8a + 4b = 0
= 2a + b = 0 ............(2)
Solve both (1) and (2) by elimination method,
- 2a + b = 1
+ 2a + b = 0
__________
0 + 2b = 1
___________
b = 1/2
Put value of b in (2)
2a + 1/2 = 0
2a = - 1/2
a = - 1/4
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