Math, asked by manvipradhan0, 1 day ago

Plz answer fast Please let me know if you are able to answer or not?​

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Answered by woriisaqt
0
Answer: 936 cm²

Step-by-step explanation:

Area of ABCD = ar Δ ADC + ar Δ ABC

Now By herons formula



For Δ ADC a= 40 cm , b= 50 cm , c= 30 cm



For Δ ABC a=28 , b=30 , c= 26



Area of ABCD = ar Δ ADC + ar Δ ABC= 600 + 336= 936 cm²

Hence, the area of quadrilateral ABCD is 936 cm²
Answered by anjanasingh79301
0

Answer:

In ΔABC

Take a = 26cm, b = 30cm and c = 28cm

So we get

s=

2

a+b+c

s=

2

26+30+28

By division

s=42cm

We know that

Area=

s(s−a)(s−b)(s−c)

By substituting the values

Area=

42(42−26)(42−30)(42−28)

So we get

Area=

42×16×12×14

It can be written as

Area=

14×3×16×4×3×14

On further calculation

Area=

14×14×3×3×16×4

So we get

Area=14×3×4×2

By multiplication

Area=336cm

We know that the diagonal divides the parallelogram into two equal area

So the area of parallelogram ABCD=Area of Δ ABC+Area of ΔACD

It can be written as

Area of parallelogram ABCD=2(Area of ΔABC)

By substituting the values

Area of parallelogram ABCD=2(336)

By multiplication

Area of parallelogram ABCD=672cm

2

Therefore, the area of parallelogram ABCD is 672cm

Step-by-step explanation:

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