Question

plz answer fast plz​

Answer 1

Simplify:

Step-by-step explanation:

$\ Given \ value:\\\\222- [\frac{1}{3} \ |42 + (56- \overline{8+9}\ ) |+108] \\\\\ Solution:\\\\ \apply \ BODMOS \ rule \\\\ 222- [\frac{1}{3} \ |42 + (56- \overline{8+9}\ ) |+108] \\\\\rightarrow 222- [\frac{1}{3} \ |42 + (56+ 1) |+108] \\\\\rightarrow 222- [\frac{1}{3} \ |42 + 57 |+108] \\\\\rightarrow 222- [\frac{1}{3} \ |99 |+108] \\\\\rightarrow 222- [\frac{1}{3} \times 99 +108] \\\\\rightarrow 222- [33 +108] \\\\\rightarrow 222- [141] \\\\\rightarrow 222- 141 \\\\\rightarrow 81$

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