Question

plz answer fast plz ​

Answer 1

a and b are the two zeroes.

k(x²-(a+b)x+ab)

k(x²-8x+12) is the required answer. 2 one is the right answer. pls mark me the brainliest

Answer 2

✪AnSwEr

${\tt{\red{\underline{\large{Given}}}}}$

• Sum of zeroes=8
• Product of zeroes=12

${\sf{\green{\underline{\large{To\:find}}}}}$

• Quadratic polynomial

${\sf{\pink{\underline{\Large{Explanation}}}}}$

Let the zeroes of the polynomial be$\tt\alpha{and}\beta$

Then,

$\tt\alpha{+}\beta{=}\dfrac{-b}{a}=8$

&

$\tt\alpha{\times}\beta{=}\dfrac{c}{a}=12$

From this we conclude that

a=1

b=-8

c=12

From quadratic polynomial

ax²+bx+c

=>x²-8x+12

Hence the quadratic polynomial be x²+8x+12