Question

plz answer fast. plz answer as expert.​ plz solve on paper.

Answer 1

see explained in pic. please select as brainliest.

Answer 2

$\frac{{(a + \frac{1}{b})}^{x}{(a - \frac{1}{b})}^{y} }{{(b + \frac{1}{a})}^{x}{(b - \frac{1}{a})}^{y} }$

Now we shall solve the x powered value and y powered value separately.

$\frac{{(a + \frac{1}{b})}^{x} }{{(b + \frac{1}{a})}^{x} } \times \frac{{(a - \frac{1}{b}})^{y} }{{(b - \frac{1}{a}})^{y} } \\ \\ = {(\frac{\frac{ab + 1}{b} }{ \frac{ab + 1}{a} })}^{x} \times {(\frac{ \frac{ab - 1}{b} }{ \frac{ab - 1}{a} } }^{y} ) \\ \\ = { (\frac{b}{a})}^{x} \times{(\frac{b}{a} )}^{y} \\ \\ ={(\frac{b}{a}) }^{x + y} (ans)$

Now, while solving separately the numerator in both the terms get cancelled out and the left fractions base become equal i.e b/a.

Hence, if base are equal then in case of multiplication powers get add up that why the answer becomes (b/a)^x+y.