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Let us say that alpha =a and beta =b
Now it is given that (a+b)^2-ab=24
Here , a+b = - coefficient of x/coefficient of x^2
So, a+b= -5/2
ab=constant term/coefficient of x^2
So, ab =k/2
Substituting ab and a+b in (a+b)^2-ab=24:-
=(-5/2)^2-k/2=24
=25/4-k/2=24
=25-2k=96
=(-2k)=96-25
= (-k)=71/2
= (-k)=35.5
=k=(-35.5)
If you find it helpful please mark it as brainliest....
Now it is given that (a+b)^2-ab=24
Here , a+b = - coefficient of x/coefficient of x^2
So, a+b= -5/2
ab=constant term/coefficient of x^2
So, ab =k/2
Substituting ab and a+b in (a+b)^2-ab=24:-
=(-5/2)^2-k/2=24
=25/4-k/2=24
=25-2k=96
=(-2k)=96-25
= (-k)=71/2
= (-k)=35.5
=k=(-35.5)
If you find it helpful please mark it as brainliest....
sahilpmn:
yur is wrong
check it again
wrong
because square of -5/2 is 25/4
check it i have rectified it
ok now it is correct
but ans what
i rectified it immediately
mark anyone of us as brainliest.....
Answered by
1
i hope my ans is correct
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