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what should be maximum average velocity of water in a tube of diameter 0.5 cm so that the flow is laminar?
Given coefficient of viscosity = 0.00125 Nsec/m².
Answers
Answered by
10
Answer is 57.5 cm/sec.
Reynolds's formula for fluid flow:
Re = row * v * D / μ
Re = Reynolds's number < 2300 for laminar stream lined non-turbulent flow.
row = density = 1000 kg/m^3
μ = dynamic or kinematic viscosity = 0.00125 Pa-s.
D = inner diameter = 0.005 meter.
So v = Re * μ / (row* D)
v < 57.5 cm/s.
Reynolds's formula for fluid flow:
Re = row * v * D / μ
Re = Reynolds's number < 2300 for laminar stream lined non-turbulent flow.
row = density = 1000 kg/m^3
μ = dynamic or kinematic viscosity = 0.00125 Pa-s.
D = inner diameter = 0.005 meter.
So v = Re * μ / (row* D)
v < 57.5 cm/s.
kvnmurty:
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Answered by
0
Answer:
Answer is 57.5 cm/sec.
Reynolds's formula for fluid flow:
Re = row * v * D / μ
Re = Reynolds's number < 2300 for laminar stream lined non-turbulent flow. row = density = 1000 kg/m^3
μ = dynamic or kinematic viscosity = 0.00125 Pa-s.
D = inner diameter = 0.005 meter.
So v = Re * μ / (row* D)
v < 57.5 cm/s.
Explanation:
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