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∆ADE is ~ to ∆ABC by AA
then,by Thales theorum
AD/DB=AE/EC
1.9/5.7=AE/EC
AE:EC=1:3
then,by Thales theorum
AD/DB=AE/EC
1.9/5.7=AE/EC
AE:EC=1:3
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AB=7.6 & AD=1.9
AB=AD+DB = 1.9 + DB
7.6-1.9=DB
5.7= DB
From Thales theorem or Basic Proportionality theorem ,
AD/DB=AE/EC
1.9/5.7=AE/EC
AE/EC=1/3
Therefore ,AE:EC=1:3
AB=AD+DB = 1.9 + DB
7.6-1.9=DB
5.7= DB
From Thales theorem or Basic Proportionality theorem ,
AD/DB=AE/EC
1.9/5.7=AE/EC
AE/EC=1/3
Therefore ,AE:EC=1:3
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