Question

plz answer faster
with explaination plzzzzzzzz ​

Answer 1

HELLO DEAR,

(81)^{0.16} * (81)^{0.09}

we know :- [mⁿ * mˣ = m⁽ⁿ ⁺ ˣ⁾]

so, ⇒(81)^{0.16 + 0.09}

⇒(81)^{0.25}

⇒(3⁴)^{0.25}

⇒(3)^{4*0.25}

⇒(3)^{1}

⇒3

I HOPE ITS HELP YOU DEAR,

THANKS

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HELLO DEAR,

(81)^{0.16} * (81)^{0.09}

we know :- [mⁿ * mˣ = m⁽ⁿ ⁺ ˣ⁾]

so, ⇒(81)^{0.16 + 0.09}

⇒(81)^{0.25}

⇒(3⁴)^{0.25}

⇒(3)^{4*0.25}

⇒(3)^{1}

⇒3

I HOPE ITS HELP YOU DEAR,

THAN

Answer 2

Question :

Find the value of

$(81) {}^{0.16} \times (81) {}^{0.09}$

Properties of Exponents

$1)a {}^{m} \times a {}^{n} = a {}^{m + n}$

$2) \frac{a {}^{m} }{a {}^{n} } = a {}^{m - n}$

$3)a {}^{m} \times b {}^{m} = (ab) {}^{mn}$

$4)a {}^{0} = 1$

Solution :

we have to find the value of

$(81) {}^{0.16} \times (81) {}^{0.09}$

use Property of Exponent$a{}^{m}+a{}^{n}=a{}^{m+n}$

$= (81) {}^{0.16 + 0.09}$

$= (81) {}^{0.25}$

$= (81) {}^{ \frac{25}{100} }$

$= (81) {}^{ \frac{1}{4} }$

$= (3 {}^{4} ) {}^{ \frac{1}{4} }$

$= 3$

it is the required solution!