Question

plz answer for this​

Answer 1

Answer:

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Answer 2

y^3-(3)^3/5y^2-16y+3 × (5y)^2-(1)^2/y^2+3y+9

(y-3)(y^2 + 3^2 + 3y) ×(5y+1)(5y-1)/y^2+3y+9×(5y^2-16y+3)

(y-3)(5y+1)(5y-1)/-5y(3-y)+3-y

(y-3)(5y+1)(5y-1) / (3-y)(-5y+1)

-1(5y+1)(-1)

= 5y+1