Question

plz answer for this 31st question in the picture​

Answer 1

Step-by-step explanation:

Given one root of the quadratic equation is -3√3.

$\sqrt{3} {x}^{2} + mx - 8 = 0$

$\sqrt{3} \times ( - {3 \sqrt{3} )}^{2} + m \times ( - 3 \sqrt{3} ) - 8 = 0$

$\sqrt{3} \times (9 \times 3) - 3 \sqrt{3} m - 8 = 0$

$\sqrt{3} \times 27 - 3 \sqrt{3} m - 8 = 0$

$27 \sqrt{3} - 3 \sqrt{3} m - 8 = 0$

$24 \sqrt{3} m = 8$

$m = \frac{8}{24 \sqrt{3} }$

$m = \frac{1}{3 \sqrt{3} }$