Question

plz answer I will mark u brainliest......​

Answer 1

Answer:

BELOW.please mark as brainliest and like this

Step-by-step explanation:

1.Solution Steps

64 { x }^{ 3 } +125 { y }^{ 3 } -64 { z }^{ 3 } +240xyz

64x

3

+125y

3

−64z

3

+240xyz

view step

64x^{3}+125y^{3}-64z^{3}+240xyz

x

64x^{3}+240yzx+125y^{3}-64z^{3}

64x

3

+240yzx+125y

3

−64z

3

(4x+5y−4z)(16x

2

−20xy+16xz+25y

2

+20yz+16z

${}^{2}$

is true

Q.2.

Rewrite 8x^{3}-278x

3

−27 as \left(2x\right)^{3}-3^{3}(2x)

3

−3

3

. The difference of cubes can be factored using the rule: a^{3}-b^{3}=\left(a-b\right)\left(a^{2}+ab+b^{2}\right)a

3

−b

3

=(a−b)(a

2

+ab+b

2

). Polynomial 4x^{2}+6x+94x

2

+6x+9 is not factored as it does not have any rational roots.

\left(2x-3\right)\left(4x^{2}+6x+9\right)

(2x−3)(4x

2

+6x+9)

Answer 2

Answer:

Step-by-step explanation: