plz answer....... if the points A (4,3 )and b (x ,5)are on the circle with Centre O (2,4) find the value of x.
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points A(4,3)
points B (X,5)
CENTER O (2,4)
value of x, =?
first need to calculate the distance between points A and points O,
root((4-2)^2)+(3-4)^2)
root(4+1)
root(5)
distance between points A and O is 2.23 units,
the distance between points B and points O,
root((x-2)^2)+(5-4)^2)=2
root((x-2)^2)+1)=2----> A
taking square on both side of equation A,
(x-2)^2=4-1
(x-2)^2=3 ----->B
now taking root on both side of equation B,
x-2=1.732
x=3.732 units
value of x is 3.732 units
bharatishita2:
but mera 0and4
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