Question

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Answer 1

Answer:

7

Step-by-step explanation:

laws of exponents$\frac{x^{a}}{x^{b}} = x^{a-b}$

$(-\frac{4}{5})^{x}/ (-\frac{4}{5})^{5} = (-\frac{4}{5})^{2}$

x - 5 = 2

x = 2 + 5

x = 7

∴$(-\frac{4}{5})^{7}/ (-\frac{4}{5})^{5} = (-\frac{4}{5})^{2}$

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