Question

plz answer.... In the quadratic equation kx square - 6 x - 1 = 0 determine the values of K for which the equation does not have any real root​

Answer 1

Answer:-

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Given equation :- kx² - 6x - 1

If the equation has no real roots then ,

b² - 4ac < 0

( - 6 )² - 4 × k × ( - 1 ) < 0

36 + 4k < 0

4k < - 36

k < - 36 / 4

k < - 9

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Thanks!

Answer 2

Answer:

Hope its help

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