Question

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Answer 1

40   +u=180  

⇒u=140  

 ω+u=180  

 ⇒ω=180°−u

=40°

∠z=70°(vertically opposite angles)

∠y+∠z=180°

⇒∠y=180°−∠z

180°−70°

=110°

⇒ω+x=180

 ∴x=140 °

$40 +u=180 ⇒u=140 ω+u=180 ⇒ω=180°−u=40°∠z=70°(vertically opposite angles)∠y+∠z=180°⇒∠y=180°−∠z180°−70°=110°⇒ω+x=180 ∴x=140 °$

Answer 2

Answer:

Consider Angle a and angles b as show in the figure.

Line p|| line q|| and line t is a transversal.

m angle a = 40°.

m angel x + m = angel a= 140°.

therefore, angel x + 40° = 180°.

Therefore, angel x = 180° - 40°.

therefore, angel x = 140°.

m angel B = 70°....(vertically opposite angels)

Line p|| Line q and line a is the transversal .

m angle Y + m angle B = 180°...(interior Angel's)

therefore angel y + 70° = 180 °.

Therefore m angel y = 180° - 70°

Hence , angel y = 110°

Hence,

m Angel x = 140 °

m angel y = 110°