Question

plz answer it correctly i req my friends its an important sum for exams plzzz!​

Answer 1

Answer:

See the explanation part

Step-by-step explanation:

9x+3y+12 = 0 ............................................................................................... (i)

18x + 6y + (2k-1) = 0 ............................................................................................... (ii)

Then, add (i) and (ii)

9x+3y+12 + 18x + 6y + (2k-1) = 0

27x+ 9y + 11 + 2k = 0

27x+ 9y + 2k = -11

x + 9y + 2k = $\frac{-11}{27}$

x+y+k = $\frac{-11}{27*9*2}$

x+y+k = $\frac{-11}{486}$

k = $\frac{-11}{486}$ - x - y  

Therefore, we conclude that the lines are parallel.