Question

Plz answer it fast....​

Answer 1

In the given question we have to find the equilibrium constant .

Let's consider the first reaction to be eq 1 an similarly second to be eq 2 and the new reaction i.e. reverse of 1 be eq3

So if we write reaction first reaction in a reverse manner then it will be written as given below and consider this new reaction to be

2H2+ O2 --2H20 so therefore K1 for it now is is reverse and let it be new suppose it is k1'= 1/k1.

Now if we add eq2 and eq 3

We get

2H2 +2CO2 — 2CO +2 H20

Therefore equivalent constant fot it will be K= K1'*K2

K= K2/k1=25

But we see if we divide the whole equation by 2 then the resultant equivalent constant will be

Square root of K and let it be K'

Therefore K'= square root of K i.e

5.0

Hence the equivalent constant for the reaction is 5.0 and we note that D is the correct answer.

Hope you understand it.

Thanks