Question

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Answer 1

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$\frac{1}{2} \frac{m}{s}$

$\huge\underline\bold\red{Explaination: }$

Let the final velocity of 4 kg ball just after collision be v. Since, external force is gravitational which is non - impulsive, hence, linear momentum will be conserved.

Applying linear momentum conservation

$2( - 3) + 4(4) = 2(4) + 4(v)$

$or \: v \: = \frac{1}{2} metre \: pr \: second$

Hence, the velocity of 4 kg ball just after collision is 1/2 m/s

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