Question

plz answer it fast ........ answer complete section A

Answer 1

1. 5 ( when we multiply given polynomial, we will get that degree is 5)
2. 0, ( as their is no variable, degree is 0)
3. 6 ( it will have tens as x^5,x^4,x^3,x^2,x^1,x,constant )
4. 0
5.As x+1 is factor, if we put x=-1, Equation becomes 0.
By putting value x=1, 2 (1)^2+ k = 0, k=-2
6.
7. 0,1,2
8. x^2 -5
9. (2)^2 -2k + 2 =0
k=3
10. 5

Answer 2

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1. 5 ( when we multiply given polynomial, we will get that degree is 5)

2. 0, ( as their is no variable, degree is 0)

3. 6 ( it will have tens as x^5,x^4,x^3,x^2,x^1,x,constant )

4. 0

5.As x+1 is factor, if we put x=-1, Equation becomes 0.

6. By putting value x=1, 2 (1)^2+ k = 0, k=-2

7. 0,1,2

8. x^2 -5

9. (2)^2 -2k + 2 =0

k=3

10. 5