plz answer it fast its a request
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Answer:
Step-by-step explanation:
__________
Given -
x-1=>0
x=>1
putting the value of x
p(x)=4x^2-3x+k
p(1)=4(1)^-3(1)+k
0=1+k
k=>-1
Answered by
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Given : x -3 is a factor of k²x³ - kx² + 3kx - k
To find : Value of k
Solution:
x - 3 is a factor of
k²x³ - kx² + 3kx - k
=> x = 3 will result in to 0
=> k²3³ - k3² + 3k(3) - k = 0
=> 27k² -9k + 9k - k = 0
=> 27k² - k = 0
=> 27k² = k
=> 27k = 1
=> k = 1/27
k = 1/27 if x -3 is a factor of k²x³ - kx² + 3kx - k
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