Question

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Answer 1

Solution:-
Given : AC = BC, angle DCA = angle ECB and angle DBC = angle EAC
∠ DCA = ∠ ECB (Given)
Adding ∠ ECD to both sides, we get
∠ DCA + ∠ ECD = ∠ ECB + ∠ ECD
Addition property
∠ ECA = ∠ DCB.
AC = BC (Given)
∠ DBC = ∠ EAC (Given)
⇒ Δ DBC ≡ Δ EAC  (By ASA postulate)
So, DC = EC          (By CPCT)
Hence proved.

Answer 2

Answer:

introduced a trial scheme into primary schools, named the ABCD of Equality that aimed to teach children that boys and girls are equal and have equal opportunities in life in a bid to scrap the idea of traditional stereotypes of jobs for boy and girls.