Question

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Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Given

Cosec θ =10/8

We know that Cosec θ = Hypotenuse/Perpendicular

Construction

Construct a Δ ABC

In which

AC = Hypotenuse = 10 units

AB= Perpendicular = 8 Units

BC= Base

For diagram refer to attachment given below

Solution

We know that Cosec θ = Hypotenuse/Perpendicular

Form ΔABC ; ∠ABC= 9

By Pythagoras theorem

BC² +AB²=AC²

BC²=AB² - BC²

BC²=10²-8²=100-64=36

BC²=36

BC = √36=6

Base = BC= 6 units

We know that

Sec θ = Hypotenuse /Base = AC/BC=10/6

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