Question

plz answer it fast plzz ​

Answer 1

Let one number M

and

Another be N

Original number (2 digit number) = 10M + N

☞ A two digit is 3 more than 4 times the sum of it's digit.

=> 10M + N = 4(M + N) + 3

=> 10M + N = 4M + 4N + 3

=> 10M - 4M + N - 4N = 3

=> 6M - 3N = 3

=> 2M - N = 1

=> - N = 1 - 2M

=> N = 2M - 1 ________(eq 1)

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☞ If 18 is added to the number. The digits are reversed.

Reversed digits (number) = 10N + M

=> 10M + N + 18 = 10N + M

=> 10M - M + N - 10N = - 18

=> 9M - 9N = - 18

=> M - N = - 2 __________(eq 2)

=> M - (2M - 1) = - 2 [From (eq 1)]

=> M - 2M + 1 = - 2

=> - M = - 3

=> M = 3

• Put value of M in (eq 1)

=> N = 2(3) - 1

=> N = 6 - 1

=> N = 5

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☞ We have to find the number.

Number = 10M + N

=> 10(3) + 5

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Number = 35

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