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Answer:
Let speed of the slow train =xkm/hr
Let speed of the fast train =[x+10]km/hr]
Time taken by slow train to cover the distance of 600km=[x+10]hr
time taken by fast train = 600/[x+10]=3
600/x-600[x+10]=3
=[x+10]-x[x+10]=3
600x+6000-600x=3[x[x+10]
6000=3x2+30x
3x2+30x-6000
0 dividing it by 3 we get
x2+10x-2000
x2+50x-40x-2000=0
x[x+50]-40[x+50]=0
[x-40] [x+50]
x=40 or -50
x =40
Speed of the slow train is 40kmhr
Speed of the fast train is 50 km/hr
Hope this helps u...
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