Plz answer it fast tomorrow is my exam
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hey !frnd here is ur ans...
opposite sides of a cyclic quadrilateral are supplementry .
hence,angle BAD+angleBCD=180°,
45°+x=180°.
x=180°-45°
hence,x=135°.
hope this may help uh....
if uh got helpful don't forget to mark as brainlist....
opposite sides of a cyclic quadrilateral are supplementry .
hence,angle BAD+angleBCD=180°,
45°+x=180°.
x=180°-45°
hence,x=135°.
hope this may help uh....
if uh got helpful don't forget to mark as brainlist....
harshlf4p50p4g:
okay check my answer too!!! and tell your thoughts on it..
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see i have solved this for you in a simple way bruh!!!
just add me as brainlist if you think it is much eaiser to understand!!!
just add me as brainlist if you think it is much eaiser to understand!!!
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