plz answer it fast very urgent.....
i need a proper solution....
best and descriptive answer will get brainliest
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If roots are equal, then D =0
b²-4ac = 0
(-4k)²-4(k+1)(9)=0
16k²-36(k+1)=0
16k²-36k-36=0
4k²-9k-9=0
4k²-12k+3k-9=0
4k(k-3)+3(k-3)=0
(4k+3)(k-3)=0
K=-3/4 and 3
b²-4ac = 0
(-4k)²-4(k+1)(9)=0
16k²-36(k+1)=0
16k²-36k-36=0
4k²-9k-9=0
4k²-12k+3k-9=0
4k(k-3)+3(k-3)=0
(4k+3)(k-3)=0
K=-3/4 and 3
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tnx a lot
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