Question

plz answer it fast with solution procedure!!! then the 4th vertex is??​

Answer 1

(0,0) , (a,0) and (b,c) are the three vertexes of parallelogram taken in order.

Let us name those points.

Let O(0,0) , A(a,0) and B(b,c) be the three vertexes of a parallelogram OABC.

We need to find coordinates of C.

OB and AC are the two diagonals of the parallelogram. We know that diagonals of a parallelogram bisect each other. That is, the diagonals have a common midpoint. Let the midpoint be M(x,y).

By midpoint formula, we can find the coordinates of M.

Midpoint of diagonal OB

$x = \frac{0+b}{2} = \frac{b}{2}$

$y = \frac{0+c}{2} = \frac{c}{2}$

So coordinates of M $(\frac{b}{2} ,\frac{c}{2})$.

This is the midpoint of diagonal AC as well. Let coordinates of C (x',y')

By midpoint formula

$\frac{b}{2} = \frac{a+x'}{2}\\ x' = (b-a)$

$\frac{c}{2} = \frac{0+y'}{2}\\ y' = c$

So the fourth vertex is

(b-a , c)

Answer 2

Answer:

Hey mate I don't want to answer Ur question as u are not a promiseable girl

come to my Breakfast Question If u want to chat

Take Care...

# Indians Fights Against Corona...