Question

plz answer it guys.....​

Answer 1

Step-by-step explanation:

Let x (0 < x < 12) cm, be the length of each side of the square which is to be cut from each corner of the rectangular tin sheet of size 45 cm by 24 cm. Let V the volume of the open box formed by folding up the flaps.

: V =x(45 - 2x)(24-2x) = 2(2x? - 69x² +540x)

dV

dx

dV

dx

= 2(6 x - 138 x +540)

* 2(6x - 138x+540) = 0 - x - 23x+90 = 0

= 0 (x-5) (x- 18) = 0 x = 5

= x = 5, 18

[: x = 18 € (0, 12)]

dy

= 2(12x-138)

= 2(60 - 138) = -156< 0

AtX = 5,

V has local maximum at x 5

But x = 5 is the only extreme point V is maximum when x = 5

side of the square 5 cm

thank you