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Answer:n^3-n =n (n^2-1)
=n(n+1)(n-1)
On dividing any no.x by 6,
We get 6q+r
r=1,2,3,4,5,0
If r=0, x=6q
6 will be definitely div. by one of n,n+1,n-1....
It will continue till 6q+5
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