Math, asked by deepu4268, 9 months ago

Plz answer it guys plzzzzzzzz ​

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Answered by Siddharta7
0

Step-by-step explanation:

\bold{Given : } \sqrt[4]{\sqrt[3]{2^2}}

\Rightarrow \sqrt[4]{(2^2)^{\frac{1}{3}}}

\Rightarrow \sqrt[4]{(2)^{\frac{2}{3}}}

\Rightarrow 2^{\frac{2}{3} * \frac{1}{4}}

\Rightarrow 2^{\frac{1}{6}}

Hope it helps!

Answered by ayush33475627
0

Answer:

  = \sqrt[4]{ \sqrt[ 3]{2 {}^{2} }}

 \sqrt[4]{ ({2}^{2}) \frac{1}{3}  }

 \sqrt[4]({2}) \frac{2}{3}

2 \frac{2}{3}  \times  \frac{1}{4}

 = 2 \frac{1}{6}

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