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Answer:
option C
Explanation:
1gm ion of Al³+ion = 27gm
However, 27gm is also the molar mass of aluminium and , we know there are 6.022 x 10²³particles of a substance in molar mass of a substance. So,
27gm of Al³+ = 6.022 x 10²³Al³+ ions
charge on one Al³+ = 3eC
So, charge on 6.022 x 10²³ Al³+ ions = 3eC x Na
Hence charge on 1g ion of Al³+ would be = 3/27 x Na x eC
So, the correct option is C ---> 1/9 Na e Coulombs
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