plz answer it..I WILL MARK YOU AS BRAINLIEST...!!!!
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Step-by-step explanation:
a²-3a+2
=a²-2a-a+2
=a(a-2)-1(a-2)
=(a-1)(a-2)
(a-1)x² + (a²-1)x+(a-1)(a-2)=0
Discriminant = b²-4ac
(a²-1)² - 4(a-1)(a-1)(a-2)
=(a+1)²(a-1)² - 4(a-1)²(a-2)
=(a-1)²[(a+1)²-4(a-2)]
=(a-1)²[a²-2a+1-4a+8]
=(a-1)²(a²-6a+9)
=(a-1)²(a-3)²
√b²-4ac = (a-1)(a-3)
Roots = -b±√b²-4ac/2a
= -(a²-1) ±(a-1)(a-3)/2(a-1)
= -(a+1)(a-1)±(a-1)(a-3)/2(a-1)
= -(a+1)±(a-3)/2
=-(a+1)+(a-3)/2 or -(a+1)-(a-3)/2
= (-a-1+a-3)/2 or (-a-1-a+3)/2
= -4/2 or -2a/2
= -2 or -a
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