plz answer .it is important
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nikkichoudhary17:
hii Aditya
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/_GAF =100°
/_GAF=EFA( •.• Alternative interior angles )
/_EFA = 100°
x = /_EFA÷2 (•.• BF bisects /_F )
x = 100°÷2
=50°
.•. x = 50°
/_GAF=EFA( •.• Alternative interior angles )
/_EFA = 100°
x = /_EFA÷2 (•.• BF bisects /_F )
x = 100°÷2
=50°
.•. x = 50°
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wrong h
kahan de rakha hai ki bf bisects angle f
Answered by
2
no it can't be solved as i have tried but x is cutting with -x ,,
sorry
sorry
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thanx bro
hey can u tell me how to delete comments
how i don't know
could u ths
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thanks a lot
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