plz answer it it I will get scolded PLEASEEEEEEEE
Attachments:
Answers
Answered by
2
mass of the metal piece = 200 g
Initial temperature =20 °C
Final temperature =220°C
change in temperature = 220-20 = 200C
specific heat capacity (c) = 0.09
As per the formula ,
Q = m c ∆ T
Q = Heat
m = mass of the metal piece
c = specific heat capacity
∆T = change in temperature
Q = 200×0.09×200
Q = 4 ×10^4 ×0.09
Q = 3600 J
Similar questions