Question

plz answer it it I will get scolded PLEASEEEEEEEE​

Answer 1

mass of the metal piece = 200 g

Initial temperature =20 °C

Final temperature =220°C

change in temperature = 220-20 = 200C

specific heat capacity (c) = 0.09

As per the formula ,

Q = m c ∆ T

Q = Heat

m = mass of the metal piece

c = specific heat capacity

∆T = change in temperature

Q = 200×0.09×200

Q = 4 ×10^4 ×0.09

Q = 3600 J