Question

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Answer 1

Answer:

7 cm (approx)

Step-by-step explanation:

take ∆ADB

$\tan(45) = \frac{ab}{db}$

therefore

DB=9√3 m

in ∆ABC

$\tan(60) = \frac{ab}{bc} \\ \sqrt{3} = \frac{9 \sqrt{3} }{bc} \\ bc = 9 \: cm$

therefore

CD = BD-BC

CD=9(√3-1)=9*0.73=6.57~7cm

Answer 2

Step-by-step explanation:

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plz answer it