Math, asked by tejalingle81, 3 months ago

Plz answer it ....plz plz plz ​

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Answered by ItzPreyashi
84

Answer:

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First we have to find the product.

5 × (x²+y²+z²+3xy-yz+zx)

=> 5x²+5y²+5z²+15xy-5yz+5zx

Let's find the sum :

(xy+zx+yz) + (3xy-y²+z²-x²+8yz)

=> xy+3xy +yz+8yz+zx-y²+z²-x²

=> 4xy + 9yz +zx-y²+z²-x²

We have to subtract the sum from the product :

(5x²+5y²+5z²+15xy-5yz+5zx) - (4xy + 9yz + zx - y² + z² - x²)

=> 5x²+5y²+5z²+15xy-5yz+5zx - 4xy-9yz-zx+y²-z²+x²

=> 5x²+x²+5y²+y²+5z²-z²+15xy-4xy-5yz-9yz+5zx-zx

=> 6x²+6y²+4z²+11xy-14yz+4zx

So , the answer is 6x²+6y²+4z²+11xy-14yz+4zx.

HOPE IT HELPS UH...!!

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